document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249403>Question 249403</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diagonal of a television set is 52 inches long. Its length is 28 inches more than its height. Find the dimensions of the television set. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181661 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181661\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (28+x)^2+x^2=52^2<BR>\n" );
document.write( "784+56x+x^2+x^2=2,704<BR>\n" );
document.write( "2x^2+56x+784-2,704<BR>\n" );
document.write( "2x^2+56x-1,920=0<BR>\n" );
document.write( "2(x^2+28x-960)=0<BR>\n" );
document.write( "2(x-20)(x+48)=0<BR>\n" );
document.write( "x-20=0<BR>\n" );
document.write( "x=20 inches for the height<BR>\n" );
document.write( "20+28=48 inches for the length.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "48^2+20^2=52^2<BR>\n" );
document.write( "2,304+400=2,704<BR>\n" );
document.write( "2,704=2,704<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );