document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31494>Question 31494</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let p,q be the roots of the equation (x-a)(x-b)=c with c<>0.Then the roots of the equation (x-p)(x-q)+c=0 are which of the following:-<BR>\n" );
document.write( "A.a,b<BR>\n" );
document.write( "B.a,c<BR>\n" );
document.write( "C.b,c<BR>\n" );
document.write( "D.a,b,c </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18165 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18165\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> None of the given options hold true here.\r<BR>\n" );
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document.write( "Let us consider a=b=2; and c=9 in the given equation (x-a)(x-b)=c<BR>\n" );
document.write( "So, (x-2)^2=9=>(x-2)=3 or (x-2)=-3<BR>\n" );
document.write( "=>x=5 or x=-1; same as p=5 and q=-1\r<BR>\n" );
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document.write( "This comes down to 5(value of p) and -1(value of q) are the roots of the equation (x-a)(x-b)=c where a=2, b=2 and c=9; \r<BR>\n" );
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document.write( "Now,<BR>\n" );
document.write( "(x-p)(x-q)+c=0  gives<BR>\n" );
document.write( "(x-5)(x+1)+9=0<BR>\n" );
document.write( "=>x^2-4x-5+9=0<BR>\n" );
document.write( "=>x^2-4x+4=0<BR>\n" );
document.write( "=>(x-2)^2=0<BR>\n" );
document.write( "=>x=2 or x=-2<BR>\n" );
document.write( "The roots of the given equation are 2 and -2\r<BR>\n" );
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document.write( "The roots contradict with all given options in terms of a, b, or c </SPAN>\n" );
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