document.write( "Question 249372: I need to solve this conditional proof and I can't. Help?\r
\n" );
document.write( "\n" );
document.write( "1. ~(M.~L)->Q\r
\n" );
document.write( "\n" );
document.write( ":. ~L->Q \n" );
document.write( "
Algebra.Com's Answer #181645 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Note: With conditional proofs, we assume the antecedent of the conclusion. In this case, we're assuming ~L which we'll denote with C.P (for conditional proof). Also, I'm going to use '&' in place of '.'\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "1. ~(M & ~L) -> Q / :. ~L -> Q\r\n" ); document.write( "-------------------------\r\n" ); document.write( "2. ~L C.P.\r\n" ); document.write( "3. ~~(M & ~L) v Q 1 Material Implication\r\n" ); document.write( "4. (M & ~L) v Q 3 Double Negation\r\n" ); document.write( "5. Q v (M & ~L) 4 Commutation\r\n" ); document.write( "6. (Q v M) & (Q v ~L) 5 Distribution\r\n" ); document.write( "7. (Q v ~L) & (Q v M) 6 Commutation\r\n" ); document.write( "8. Q v ~L 7 Simplification\r\n" ); document.write( "9. ~~Q v ~L 8 Double Negation\r\n" ); document.write( "10. ~Q -> ~L 9 Material Implication\r\n" ); document.write( "11. ~L v ~L 2 Addition\r\n" ); document.write( "12. ~~L v ~L 11 Double Negation\r\n" ); document.write( "13. L -> ~L 12 Material Implication\r\n" ); document.write( "14. ~L -> ~~L 13 Transposition\r\n" ); document.write( "15. ~L -> L 14 Double Negation\r\n" ); document.write( "16. ~Q -> L 10,15 Hypothetical Syllogism\r\n" ); document.write( "17. ~L -> ~~Q 16 Transposition\r\n" ); document.write( "18. ~L -> Q 17 Double Negation\r\n" ); document.write( "\n" ); document.write( " |