document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249378>Question 249378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is 8 feet long and 6 feet wide. if each dimension is increased by the same number of feet, a new rectangle is formed whose area exceeds the area if the original rectangle by 72 square feet. find the dimensions of the new rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181641 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let a=area of rectangle with sides 8 ft and 6 ft<BR>\n" );
document.write( "add x to each dimension<BR>\n" );
document.write( "what is the formula for area of a rectangle?<BR>\n" );
document.write( "formula=a<BR>\n" );
document.write( "formula2=a+72=(8+x)(6+x)<BR>\n" );
document.write( "what is a?<BR>\n" );
document.write( "a=Length * width<BR>\n" );
document.write( "substitute a  below\r<BR>\n" );
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document.write( "a+72=(8+x)(6+x)\r<BR>\n" );
document.write( "\n" );
document.write( "multiply out and find x\r<BR>\n" );
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document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );