document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31499>Question 31499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am submitting this problem again because from the last help I got my teacher said that it was wrong.  Please help me!<BR>\n" );
document.write( "Complete the square <BR>\n" );
document.write( "Give the Vertex <BR>\n" );
document.write( "Give the Axis <BR>\n" );
document.write( "Give the x-intercepts <BR>\n" );
document.write( "Give the y-intercept <BR>\n" );
document.write( "Give a point symmetric to the y-intercept. <BR>\n" );
document.write( "You must draw the graph using a graphing utility and attach it in your response.<BR>\n" );
document.write( "y  =  x2 -2x-3 <BR>\n" );
document.write( "He keeps telling me that I need to factor it correctly.  I have tried from the example that was given that was kind of like my problem but he told me it was wrong.  Could someone please help me with this problem?  Thank you so very much.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18163 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18163\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Factorise it: (x-3)(x+1) so the x-intercepts are at x=-1 and x=3\r<BR>\n" );
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document.write( "Complete the square: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x%5E2-2x-3+ ALIGN=MIDDLE  ALT=\"+x%5E2-2x-3+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "2a=2<BR>\n" );
document.write( "a=1<BR>\n" );
document.write( "--> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2+=+1 ALIGN=MIDDLE  ALT=\"a%5E2+=+1\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "--> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x%5E2-2x%28%2B1-1%29-3+ ALIGN=MIDDLE  ALT=\"+x%5E2-2x%28%2B1-1%29-3+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "--> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28x%5E2-2x%2B1%29-1-3+ ALIGN=MIDDLE  ALT=\"+%28x%5E2-2x%2B1%29-1-3+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "--> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28x-1%29%5E2-4+ ALIGN=MIDDLE  ALT=\"+%28x-1%29%5E2-4+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So, the vertex is at (1,-4) meaning that the line of symmetry in the function is at x=1.\r<BR>\n" );
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document.write( "Y-intercept is when x=0, so from <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+y+=+x%5E2-2x-3+ ALIGN=MIDDLE  ALT=\"+y+=+x%5E2-2x-3+\"   DISABLED_style= \"max-width:90%; height:auto;\" >, we get <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+y+=+%280%29%5E2-2%280%29-3+ ALIGN=MIDDLE  ALT=\"+y+=+%280%29%5E2-2%280%29-3+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "--> y= -3.\r<BR>\n" );
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document.write( "A point symmetric to the y-intercept (0,-3) is (2,-3) since both points are equi-distant from the line x=1.\r<BR>\n" );
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document.write( "All seen on <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28300%2C300%2C-6%2C6%2C-10%2C10%2Cx%5E2-2x-3%29+ ALIGN=MIDDLE  ALT=\"+graph%28300%2C300%2C-6%2C6%2C-10%2C10%2Cx%5E2-2x-3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "As for \"give the axis\"... what axis?\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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