document.write( "Question 249371: Solve the equation.\r
\n" ); document.write( "\n" ); document.write( "x(x - 3) = 40
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Algebra.Com's Answer #181619 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
multiply out
\n" ); document.write( "x(x - 3) = 40
\n" ); document.write( "x^2-3x-40=0
\n" ); document.write( "this can be factored
\n" ); document.write( "What are the factors of 40?\r
\n" ); document.write( "\n" ); document.write( "40,1
\n" ); document.write( "20,2
\n" ); document.write( "10,4
\n" ); document.write( "8,5
\n" ); document.write( "prime factors are
\n" ); document.write( "2,2,2,5,1\r
\n" ); document.write( "\n" ); document.write( "We want two numbers that add up to 3 or differ by three
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