document.write( "Question 249371: Solve the equation.\r
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document.write( "x(x - 3) = 40 \n" );
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Algebra.Com's Answer #181619 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! multiply out \n" ); document.write( "x(x - 3) = 40 \n" ); document.write( "x^2-3x-40=0 \n" ); document.write( "this can be factored \n" ); document.write( "What are the factors of 40?\r \n" ); document.write( "\n" ); document.write( "40,1 \n" ); document.write( "20,2 \n" ); document.write( "10,4 \n" ); document.write( "8,5 \n" ); document.write( "prime factors are \n" ); document.write( "2,2,2,5,1\r \n" ); document.write( "\n" ); document.write( "We want two numbers that add up to 3 or differ by three \n" ); document.write( " \n" ); document.write( " |