document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249334>Question 249334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 10% salt solution should be added to 20 gallons of a 60% salt solution to obtain a 50% salt solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181586 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .60*20+.10x=.50(20+x)<BR>\n" );
document.write( "12+.10x=10+.50x<BR>\n" );
document.write( ".10x-.50x=10-12<BR>\n" );
document.write( "-.4x=-2<BR>\n" );
document.write( "x=-2/-.40<BR>\n" );
document.write( "x=5 gallons of 10% salt solution is added.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".60*20+.10*5=.5(20+5)<BR>\n" );
document.write( "12+.5=.5*25<BR>\n" );
document.write( "12.5=12.5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );