document.write( "Question 249084: The width of a rectangle is 5 meters less than twice its length. If its area is 88 square meters, find the dimensions of the rectangle.\r
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Algebra.Com's Answer #181481 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
\"W+=+2L+-+5\"
\n" ); document.write( "\"A+=+L+%2A+W+=+88\"
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\n" ); document.write( "Substitute
\n" ); document.write( "\"A+=+L+%2A+%282L-5%29\"
\n" ); document.write( "\"88+=+2L%5E2+-+5L\"
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\n" ); document.write( "Subtract 88 from both sides
\n" ); document.write( "\"0+=+2L%5E2+-5L+-88\"
\n" ); document.write( "so
\n" ); document.write( "\"2L%5E2+-5L+-+88+=+0\"
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\n" ); document.write( "Can you factor this? Yes.
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\n" ); document.write( "\"%282L+%2B11%29%28L+-+8%29+=+0\"
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\n" ); document.write( "So our candidate solutions are L = -5.5 and L = 8.
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\n" ); document.write( "A negative number for the side of the rectangle is nonsense. So our answer is L = 8.
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\n" ); document.write( "Recall
\n" ); document.write( "\"W+=+2L+-+5\"
\n" ); document.write( "so
\n" ); document.write( "\"W+=+2%2A8+-+5+=+16+-+5+=+11\"
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\n" ); document.write( "With L = 8 and W = 11, the area = 88.
\n" ); document.write( "So we're done.
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