document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249077>Question 249077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of bacteria growing in an incubation culture increases with time according to B(t) = 3300(2)x, where x is time in days. Find the number of bacteria when x = 0 and x = 3.\r<BR>\n" );
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document.write( "Can you please help solve? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181478 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181478\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number of bacteria growing in an incubation culture increases with time according to B(t) = 3300(2)^x, where x is time in days. Find the number of bacteria when x = 0 and x = 3.<BR>\n" );
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document.write( "B(0) = 3300*2^0 = 3300*1 = 3300<BR>\n" );
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document.write( "B(3) = 3300*2^3 = 3300*8 = 26,400<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
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