document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=248944>Question 248944</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We have these word problems to do and they are so difficult for me to complete. Once I find the equations I can pretty much finish the problem but finding the equations is proving to be challenging. Please help.\r<BR>\n" );
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document.write( "Word Problem: A rancher can affors 300 feet of fencing to build a corral that's divided into two equal rectangles. What dimensions will maximize the corral's area?\r<BR>\n" );
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document.write( "I'm given a picture where the length is 2x and the width is y and the hint from my teacher was to use the distance formula. I'm completely lost. Thank you in advance for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181461 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181461\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Word Problem: A rancher can afford 300 feet of fencing to build a corral that's divided into two equal rectangles.<BR>\n" );
document.write( " What dimensions will maximize the corral's area?<BR>\n" );
document.write( "I'm given a picture where the length is 2x and the width is y<BR>\n" );
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document.write( "I have no idea why you would use distance formula, perhaps he meant the perimeter formula<BR>\n" );
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document.write( "The fence equation<BR>\n" );
document.write( "2(2x) + 3y = 300<BR>\n" );
document.write( "4x + 3y = 300<BR>\n" );
document.write( "3y = (300 - 4x)<BR>\n" );
document.write( "y = 100 - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F3 ALIGN=MIDDLE  ALT=\"4%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x<BR>\n" );
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document.write( "Area = L * W<BR>\n" );
document.write( "A = 2x * y<BR>\n" );
document.write( "Replace y with(100-<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F3 ALIGN=MIDDLE  ALT=\"4%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x)<BR>\n" );
document.write( "A = 2x(100-<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F3 ALIGN=MIDDLE  ALT=\"4%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x)<BR>\n" );
document.write( "A = 200x - 2x(<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F3 ALIGN=MIDDLE  ALT=\"4%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x)<BR>\n" );
document.write( "A = 200x -<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%2F3 ALIGN=MIDDLE  ALT=\"8%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x^2<BR>\n" );
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document.write( "A quadratic equation, the max area occurs at the axis of symmetry<BR>\n" );
document.write( "The formula for that: x = -b/(2a)<BR>\n" );
document.write( "In this equation a=-8/3; b=200<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-200%2F%282%28-8%2F3%29%29 ALIGN=MIDDLE  ALT=\"-200%2F%282%28-8%2F3%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-200%2F%28-16%2F3%29 ALIGN=MIDDLE  ALT=\"-200%2F%28-16%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = -200 * <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3%2F16 ALIGN=MIDDLE  ALT=\"-3%2F16\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = +37.5<BR>\n" );
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document.write( "Find y:<BR>\n" );
document.write( "y = 100 - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F3 ALIGN=MIDDLE  ALT=\"4%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x<BR>\n" );
document.write( "y = 100 - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F3 ALIGN=MIDDLE  ALT=\"4%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >*37.5<BR>\n" );
document.write( "y = 100 - 50<BR>\n" );
document.write( "y = 50 ft<BR>\n" );
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document.write( "Since the dimensions are are 2x by y, max area occurs when:<BR>\n" );
document.write( "2(37.5) = 75 ft is the length and 50 ft is the width<BR>\n" );
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document.write( "Check the perimeter (fence length)<BR>\n" );
document.write( "2(75) + 3(50) =<BR>\n" );
document.write( "150 + 150 = 300<BR>\n" );
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document.write( "C </SPAN>\n" );
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