document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249056>Question 249056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> SOLVE EACH  SYSTEM BY SUBSTITUTION<BR>\n" );
document.write( "[x=y-8<BR>\n" );
document.write( "[-x-y=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181457 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=y-8 [substitue this equation into the second equation wherever there is an \"x\"]\r<BR>\n" );
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document.write( "-x-y=0 [second equation]<BR>\n" );
document.write( "-(y-8)-y=0 [plug-in first equation for \"x\"]<BR>\n" );
document.write( "-y+8-y=0 [solve for the y-value]<BR>\n" );
document.write( "-2y+8=0<BR>\n" );
document.write( "-2y=-8<BR>\n" );
document.write( "-2y/-2=-8/-2<BR>\n" );
document.write( "y=4<BR>\n" );
document.write( "check by plugging \"x\" back into either equation. </SPAN>\n" );
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