document.write( "Question 248666: Anne and Nancy use a metal alloy that is a 24.9% copper to make jewelry. How many ounces of 20% alloy must be mixed with a 27% alloy to form 100 ounces of the desired alloy? \n" ); document.write( "
Algebra.Com's Answer #181452 by ankor@dixie-net.com(22740)\"\" \"About 
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Anne and Nancy use a metal alloy that is a 24.9% copper to make jewelry.
\n" ); document.write( " How many ounces of 20% alloy must be mixed with a 27% alloy to form 100 ounces of the desired alloy?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 20% alloy
\n" ); document.write( "then
\n" ); document.write( "(100 - x) = amt of 27% alloy
\n" ); document.write( ":
\n" ); document.write( ".20x + .27(100-x) = .249(100)
\n" ); document.write( ":
\n" ); document.write( ".20x + 27 - .27x = 24.9
\n" ); document.write( ":
\n" ); document.write( ".20x - .27x = 24.9 - 27
\n" ); document.write( ":
\n" ); document.write( "-.07x = -2.1
\n" ); document.write( "x = \"%28-2.1%29%2F%28-.07%29\"
\n" ); document.write( "x = 30 oz of 20% alloy required
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\n" ); document.write( "Check solution:
\n" ); document.write( ".20(30) + .27(70) =
\n" ); document.write( "6 + 18.9 = 24.9 \n" ); document.write( "
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