document.write( "Question 249045: solve this matrix equation.\r
\n" ); document.write( "\n" ); document.write( "x+y=1
\n" ); document.write( "4x-3y=11
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Algebra.Com's Answer #181441 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Step 1) Convert the system \r
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\n" ); document.write( "\n" ); document.write( "\"system%28x%2By=1%2C4x-3y=11%29\"\r
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\n" ); document.write( "\n" ); document.write( "into the augmented matrix\r
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\n" ); document.write( "\n" ); document.write( "\"%28matrix%282%2C3%2C1%2C1%2C1%2C4%2C-3%2C11%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Take note that the coefficients form the first 2x2 block and the right hand values form the last column. Visually, the correspondence is\r
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\n" ); document.write( "\n" ); document.write( "This conversion of notation allows us to ignore the variables (for now) since everything is based off of the numerical coefficients and right hand values.\r
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\n" ); document.write( "\n" ); document.write( "Step 2) Row Reduction\r
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\n" ); document.write( "\n" ); document.write( "Our next step is to row reduce the matrix \"%28matrix%282%2C3%2C1%2C1%2C1%2C4%2C-3%2C11%29%29\" into row reduced echelon form (rref form). (Note: Solution provided by the Linear Algebra Toolkit)\r
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\n" ); document.write( "\n" ); document.write( "Looking at the last matrix \"%28matrix%282%2C3%2C1%2C0%2C2%2C0%2C1%2C-1%29%29\", the last column has the values 2 and -1 in it. So this means that the solution is \"x=2\" and \"y=-1\" forming the ordered pair (2,-1).
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