document.write( "Question 249016: susan rode her bicycle out into the country for a distance of 24 miles. on the way back, she took a much shorter route of 12 miles and made return trip in one half hour less time. if her rate out into the country was 4 miles per hour faster than her rate on teh return trip, find both rates. \n" ); document.write( "
Algebra.Com's Answer #181411 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "24=(R+4)T OUT TRIP. \n" ); document.write( "T=24/(R+4) EQ. # 1 \n" ); document.write( "12=R(T-.5) RETURN TRIP. \n" ); document.write( "12=RT-.5R \n" ); document.write( "12+.5R=RT \n" ); document.write( "T=(12+.5R)/R EQ # 2 \n" ); document.write( "SET THE 2 T EQUATIONS EQUAL & SOLVE FOR R. \n" ); document.write( "24/(R+4)=(12+.5R)/R CROSS MULTIPLY \n" ); document.write( "24R=(R+4)(12+.5R) \n" ); document.write( "24R=12R+48+2R+.5R^2 \n" ); document.write( "2R^2+14R+48-24R=0 \n" ); document.write( ".5R^2-10R+48=0 MULTIPLY BY 2 \n" ); document.write( "R^2-20R+96=0 FACTOR. \n" ); document.write( "(R-12)(R-8)=0 \n" ); document.write( "R-12=0 \n" ); document.write( "R=12 ANS. T=1.5 ANS \n" ); document.write( "R-8=0 \n" ); document.write( "R=8 ANS. T=2 ANS. \n" ); document.write( " |