document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=249008>Question 249008</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving please:\r<BR>\n" );
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document.write( "When the length of a square is increased by 6 and the width is decreased by 4, the area remains unchanged.  Find the dimensions of the square.\r<BR>\n" );
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document.write( "Thank you!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181403 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When the length of a square is increased by 6 and the width is decreased by 4, the area remains unchanged. Find the dimensions of the square. \r<BR>\n" );
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document.write( "Let x be the length of a side of the square.<BR>\n" );
document.write( "Then x*x = x^2 is the area of the square.\r<BR>\n" );
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document.write( "From the givens we have:\r<BR>\n" );
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document.write( "(x+6)*(x-4) = x^2\r<BR>\n" );
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document.write( "Expanding we have:\r<BR>\n" );
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document.write( "x^2 + 2*x - 24 = x^2\r<BR>\n" );
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document.write( "Simplifying:\r<BR>\n" );
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document.write( "2*x = 24<BR>\n" );
document.write( "x = 12\r<BR>\n" );
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