document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=248874>Question 248874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The volume, V, of a given mass of a gas varies directly as the temperature, T, and inversely as the pressure, if V=231cm^3 when T=42 and P=20kg/cm^2, what is the volume when T=30 and P=15kg/cm? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181376 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> V = k*T/P where:\r<BR>\n" );
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document.write( "V = volume<BR>\n" );
document.write( "T = temperature<BR>\n" );
document.write( "P = pressure<BR>\n" );
document.write( "k = constant of variation.\r<BR>\n" );
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document.write( "When:\r<BR>\n" );
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document.write( "V = 231 cm^3<BR>\n" );
document.write( "T = 42 degrees<BR>\n" );
document.write( "P = 20kg/cm^2,\r<BR>\n" );
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document.write( "The formula becomes:\r<BR>\n" );
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document.write( "231 = k*42/20\r<BR>\n" );
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document.write( "Solve for k to get:\r<BR>\n" );
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document.write( "k = 110\r<BR>\n" );
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document.write( "The constant of variation is equal to 110.\r<BR>\n" );
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document.write( "When T = 30 and P = 15 and k = 110, the formula becomes:\r<BR>\n" );
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document.write( "V =  30*110/15 = 220 cm^3\r<BR>\n" );
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document.write( "Here's a <a  rel=nofollow HREF= \"http://www.regentsprep.org/Regents/math/algtrig/ATE7/Inverse%20Variation.htm\" target = \"_blank\">reference</a> that explains how the variation formulas work.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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