document.write( "Question 248916: how do you solve
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document.write( " a
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document.write( " ____ >0? by using interval notation and graphing it?
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document.write( " a+2 \n" );
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Algebra.Com's Answer #181367 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how do you solve \r \n" ); document.write( "\n" ); document.write( "a \n" ); document.write( "____ > 0? by using interval notation and graphing it? \n" ); document.write( "a+2 \n" ); document.write( "--------------------- \n" ); document.write( "1st: Notice that a cannot be -2 because of the denominator. \n" ); document.write( "--- \n" ); document.write( "2nd: Solve the EQUALITY which is the boundary for the INEQUALITY. \n" ); document.write( "a/(a+2) = 0 \n" ); document.write( "Solution: a = 0 \n" ); document.write( "---------------------- \n" ); document.write( "3rd: Draw a number line and plot a = -2 and a = 0 \n" ); document.write( "---------------------- \n" ); document.write( "4th: Pick a check point from each of the three number line intervals \n" ); document.write( "to see where the solutions for the INEQUALITY lie. \n" ); document.write( "Test the check point values in a/(a+2) > 0 \n" ); document.write( "--- \n" ); document.write( "If a = -3 you get: -3/(-1) > 0 ; true, so solutions in (-inf,-2) \n" ); document.write( "If a = -1 you get: -1/(1) > 0 ; false, so no solutions in (-2,0) \n" ); document.write( "If a = 1 you get: 1/(3) > 0 ; true, so solutions in (0,+inf) \n" ); document.write( "----- \n" ); document.write( "Final answer: (-inf,-2)U(0,+inf) \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "stan H. \n" ); document.write( " |