document.write( "Question 248810: Sam can mow a lawn in 20 minutes and Robert can mow the same lawn in 30 minutes. If they worked together, how long would it take them to do the work?\r
\n" ); document.write( "\n" ); document.write( "I need the rate of work (R), the time of work (T) , and the work done (W)
\n" ); document.write( "the equation is RT = W. \r
\n" ); document.write( "\n" ); document.write( "It would help if I am provided a detailed explanation
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Algebra.Com's Answer #181336 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
The critical insight is that you have to get the equations in terms of accomplishing 1 job.
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\n" ); document.write( "Sam can do the job in 20 min. So he can do the whole job at the rate of 1 job in 20 minutes.
\n" ); document.write( "So he does 1/20 of the job per minute.
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\n" ); document.write( "Rob can do the job in 30 min. His rate is 1/30 of the job per minute.
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\n" ); document.write( "Working together how does it take?
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\n" ); document.write( "1/20*x + 1/30*x = 1 job done
\n" ); document.write( ", where x = minutes.
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\n" ); document.write( "Multiply everything by 60 go get rid of the fractions.
\n" ); document.write( "3x + 2x = 60
\n" ); document.write( "5x = 60
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\n" ); document.write( "Divide both sides by 12
\n" ); document.write( "x = 12
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\n" ); document.write( "So our candidate answer is working together it will take them 12 minutes.
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\n" ); document.write( "Let's check.
\n" ); document.write( "In 12 minutes, Sam does 12/20 of the job and Rob does 12/30 of the job.
\n" ); document.write( "12/20 = .6
\n" ); document.write( "12/30 = .4
\n" ); document.write( "Total = 1 job done.
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