document.write( "Question 248814: One pipe can fill a tank in 20 minutes. A second pipe can fill the tank in 30 minutes. If the tank is empty, how long would be required for the two pipes operating together to fill it?\r
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\n" ); document.write( "\n" ); document.write( "I need the rate of work (R), the time of work (T) , and the work done (W)
\n" ); document.write( "the equation is RT = W. \r
\n" ); document.write( "\n" ); document.write( "It would help if I am provided a detailed explanation
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Algebra.Com's Answer #181302 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
One pipe can fill a tank in 20 minutes. A second pipe can fill the tank in 30 minutes. If the tank is empty, how long would be required for the two pipes operating together to fill it? \r
\n" ); document.write( "\n" ); document.write( "I need the rate of work (R), the time of work (T) , and the work done (W)
\n" ); document.write( "the equation is RT = W.
\n" ); document.write( "It would help if I am provided a detailed explanation
\n" ); document.write( "0 solutions
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\n" ); document.write( "1st Pipe DATA:
\n" ); document.write( "time = 20 min/job ; rate + 1/20 job/min
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\n" ); document.write( "2nd Pipe DATA;
\n" ); document.write( "time = 30 min/job ; rate = 1/30 job/min
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\n" ); document.write( "Together DATA:
\n" ); document.write( "time = x min/job ; rate = 1/x job/min
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\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/20 + 1/30 = 1/x
\n" ); document.write( "---
\n" ); document.write( "Multiply thru by x to get:
\n" ); document.write( "work + work = job done
\n" ); document.write( "x/20 + x/30 = 1
\n" ); document.write( "Multiply thru by 60:
\n" ); document.write( "3x + 2x = 60
\n" ); document.write( "5x = 60
\n" ); document.write( "x = 12 min (time needed to complete the job when both pipes are operating)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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