document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=248716>Question 248716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> for problems 7-9 solve the system of equations using addition to eliminate one variable. if the system has no solution indicate that it is inconsistent. if it has infinite solutions, indicate that it is dependent. if the system check your answer.\r<BR>\n" );
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document.write( "3x-2y=-14<BR>\n" );
document.write( "3x+5y=-14\r<BR>\n" );
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document.write( "check if possible </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181265 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-2y=-14<BR>\n" );
document.write( "3x+5y=-14 \r<BR>\n" );
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document.write( "Subtract the terms of the two equations:\r<BR>\n" );
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document.write( "(3-3)*x + (-2-5)*y = -14 - (-14)<BR>\n" );
document.write( "0*x -7*y = 0<BR>\n" );
document.write( "-7y = 0<BR>\n" );
document.write( "y = 0\r<BR>\n" );
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document.write( "Substitute y=0 in the first equation:\r<BR>\n" );
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document.write( "3*x - 2*0 = -14<BR>\n" );
document.write( "3*x = -14<BR>\n" );
document.write( "x = -14/3   </SPAN>\n" );
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