document.write( "Question 248761: the perimeter of a rectangle is 202 inches. the length exceeds the width by 63 inches. What are the length and width \n" ); document.write( "
Algebra.Com's Answer #181250 by dabanfield(803)\"\" \"About 
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the perimeter of a rectangle is 202 inches. the length exceeds the width by 63 inches. What are the length and width\r
\n" ); document.write( "\n" ); document.write( "Let x = the width of the rectangle
\n" ); document.write( "Then the length must be x+63. \r
\n" ); document.write( "\n" ); document.write( "Since the area is 202 we have:\r
\n" ); document.write( "\n" ); document.write( "x*(x+63) = 202.\r
\n" ); document.write( "\n" ); document.write( "Solve for the width x and then substitute x in x+63 to get the length.
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