document.write( "Question 248761: the perimeter of a rectangle is 202 inches. the length exceeds the width by 63 inches. What are the length and width \n" ); document.write( "
Algebra.Com's Answer #181250 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! the perimeter of a rectangle is 202 inches. the length exceeds the width by 63 inches. What are the length and width\r \n" ); document.write( "\n" ); document.write( "Let x = the width of the rectangle \n" ); document.write( "Then the length must be x+63. \r \n" ); document.write( "\n" ); document.write( "Since the area is 202 we have:\r \n" ); document.write( "\n" ); document.write( "x*(x+63) = 202.\r \n" ); document.write( "\n" ); document.write( "Solve for the width x and then substitute x in x+63 to get the length. \n" ); document.write( " |