document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=248679>Question 248679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The following problem was on my final exam last night, and I cannot figure this out. I am trying to simplify this equation:\r<BR>\n" );
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document.write( "[3 + b(to power of -1)]<BR>\n" );
document.write( "over<BR>\n" );
document.write( "[2 + b(to power of -1)]\r<BR>\n" );
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document.write( "What I did was turn the b to -1 power into 1 over b. Rewrite equation as\r<BR>\n" );
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document.write( "(3 + 1 over b)<BR>\n" );
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document.write( "(2 + 1 over b)\r<BR>\n" );
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document.write( "Then I multiplied out to remover the denominator of b in each part of the overall equation. Rewrite equation as\r<BR>\n" );
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document.write( "3b+1<BR>\n" );
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document.write( "2b+1\r<BR>\n" );
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document.write( "Then i multiplied out to remove the denominator of 2b+1. Rewrite as:\r<BR>\n" );
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document.write( "(3b+1) (2b+1) which is also 6b squared + 2b + 3b + 1. Rewrite as:\r<BR>\n" );
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document.write( "6b squared + 5b + 1.\r<BR>\n" );
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document.write( "Is this correct?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181202 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181202\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> [3 + b(to power of -1)]<BR>\n" );
document.write( "over<BR>\n" );
document.write( "[2 + b(to power of -1)] <BR>\n" );
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document.write( "[3 + (1/b)]/[2 + (1/b)]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "[(3b+1)/b] / [(2b+1)/b]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Invert the denominator and multiply:\r<BR>\n" );
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document.write( "[(3b+1)/b] * [b/(2b+1)]\r<BR>\n" );
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document.write( "---<BR>\n" );
document.write( "Cancel the \"b\" factor which is common to numerator and denominator:<BR>\n" );
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document.write( "= (3b+1)/(2b+1)<BR>\n" );
document.write( "=====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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