document.write( "Question 248647: Could I please get some help with this question? A rectangular window is 10 inches longer than it is wide. If the area is 1200 square inches, find the length and width.
\n" ); document.write( "x^2+10=1200
\n" ); document.write( "x^2+10-1200=0
\n" ); document.write( "(x+?)(x-?)= (I don't know what to do here) \n" ); document.write( "
Algebra.Com's Answer #181187 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A rectangular window is 10 inches longer than it is wide. If the area is 1200 square inches, find the length and width.
\n" ); document.write( "x^2+10=1200
\n" ); document.write( "x^2+10-1200=0
\n" ); document.write( "(x+?)(x-?)= (I don't know what to do here)
\n" ); document.write( "------------------------
\n" ); document.write( "If you cannot conveniently factor the quadratic you
\n" ); document.write( "can always use the quadratic formula.
\n" ); document.write( "x = [-10 +- sqrt(100 -4*1*-1200)]/2
\n" ); document.write( "---
\n" ); document.write( "x = [-10 +- sqrt(4900)]/2
\n" ); document.write( "x = [-10 +- 70]/2
\n" ); document.write( "x = [-10-70]/2 = -40
\n" ); document.write( "x = [-10+70]/2 = 30
\n" ); document.write( "---
\n" ); document.write( "Use the positive solution.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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