document.write( "Question 248644: The so called golden rectangle is said to be extremely pleasing visually and was used often by ancient Greek and Roman Architects. The length of a golden rectangle is approx. 1.6 times the width. Find the dimensions of a golden rectangle if its area is 9000m^2. \n" ); document.write( "
Algebra.Com's Answer #181177 by dabanfield(803)\"\" \"About 
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Area of the rectangle is 9000 sq meter.
\n" ); document.write( "Let x be the width if the rectangle.
\n" ); document.write( "The length then is (1.6)*x\r
\n" ); document.write( "\n" ); document.write( "Area - Length times Width = x*(1.6)*x = 9000\r
\n" ); document.write( "\n" ); document.write( "So we have:\r
\n" ); document.write( "\n" ); document.write( "(1.6)*(x^2) = 9000\r
\n" ); document.write( "\n" ); document.write( "Solve for x to get the width then substitute that value in (1.6)*x to get the length.
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