document.write( "Question 248625: When a and b are positive integers, a < b and ab ≤ a + 3b, how many possible values are there for a? \n" ); document.write( "
Algebra.Com's Answer #181166 by jsmallt9(3758)\"\" \"About 
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If we take \"a+%3C+b\" and add 3b to each side we get:
\n" ); document.write( "\"a+%2B+3b+%3C+b+%2B+3b\"
\n" ); document.write( "or
\n" ); document.write( "\"a+%2B+3b+%3C+4b\"

\n" ); document.write( "The reason we did this is that the left side above now matches the right side of the other inequality:
\n" ); document.write( "\"ab+%3C=+a+%2B+3b\"
\n" ); document.write( "Since \"ab+%3C=+a+%2B+3b\" and \"a+%2B+3b+%3C+4b\" then
\n" ); document.write( "\"ab+%3C+4b\"
\n" ); document.write( "by the transitive property.

\n" ); document.write( "This inequality we can solve. We can divide both sides by b (without having to be concerned about reversing the inequality because we know that b is positive):
\n" ); document.write( "\"a+%3C+4\"
\n" ); document.write( "Between this and the fact that a is also positive, the possible values for a are:
\n" ); document.write( "1, 2 and 3.
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