document.write( "Question 248513: A bank contains 30 coins, consisting of nickles, quarters, and dimes.there are twice as many nickles as quarters and the remaining are dimes.if the total value of the coins is $3.35, what is the number of each type of coin in the bank? \n" ); document.write( "
Algebra.Com's Answer #181146 by oberobic(2304) ![]() You can put this solution on YOUR website! When you work with coins, you have to keep in mind that there will be counts of the coins and values of the coins to balance. \n" ); document.write( "n = number of nickels \n" ); document.write( "5n = the value of the nickels in cents \n" ); document.write( "d = number of dimes \n" ); document.write( "10d = value of the dimes in cents \n" ); document.write( "q = quarters \n" ); document.write( "25q = value of the quarters in cents \n" ); document.write( ". \n" ); document.write( "We are told the total value: \n" ); document.write( "5n + 10d + 25q = 335 cents \n" ); document.write( ". \n" ); document.write( "Note that everything needs to be in terms of cents. \n" ); document.write( ". \n" ); document.write( "We are told: \n" ); document.write( "n + d + q = 30. \n" ); document.write( ". \n" ); document.write( "We also are told: \n" ); document.write( "n = 2q \n" ); document.write( ", which means the number of nickels is twice the number of quarters. \n" ); document.write( ". \n" ); document.write( "So we have defined 3 equations and we have 3 unknowns...hmmm... \n" ); document.write( ". \n" ); document.write( "5n + 10d + 25q = 335 \n" ); document.write( "n + d + q = 30 \n" ); document.write( "n = 2q \n" ); document.write( ". \n" ); document.write( "Substituting 2q for n, we have \n" ); document.write( ". \n" ); document.write( "5(2q) + 10d + 25q = 335 \n" ); document.write( "2q + d + q = 30 \n" ); document.write( ". \n" ); document.write( "Simplifying, we have \n" ); document.write( "10q + 10d + 25q = 335 \n" ); document.write( "10d + 35q = 335 \n" ); document.write( ". \n" ); document.write( "2q + d + q = 30 \n" ); document.write( "3q + d = 30 \n" ); document.write( ". \n" ); document.write( "d = 30 - 3q \n" ); document.write( ", which seems obvious if you think about it. \n" ); document.write( ". \n" ); document.write( "10(30-3q) + 35q = 335 \n" ); document.write( "300 - 30q + 35q = 335 \n" ); document.write( "5q = 35 \n" ); document.write( "q = 7 \n" ); document.write( ", so we think we have 7 quarters \n" ); document.write( ". \n" ); document.write( "n = 2q \n" ); document.write( "n = 14 nickels \n" ); document.write( ". \n" ); document.write( "Since there are 30 coins, then there must be 9 dimes. \n" ); document.write( ". \n" ); document.write( "We can check the values to see if they total 335. \n" ); document.write( "5n + 10d + 25q = 335 cents \n" ); document.write( "5n = 5(14) = 70 cents \n" ); document.write( "7q = 7(25) = 175 cents \n" ); document.write( "9d = 9(10) = 90 cents \n" ); document.write( "70 + 175 + 90 = 335 cents \n" ); document.write( "So it checks. \n" ); document.write( "Done. \n" ); document.write( " |