document.write( "Question 248523: Please help me answer this word problem: If Mrs. Smith takes her class of 12 students to the theater. They sit in the front row where there is exactly twelve seats. There are 9 girls and 3 boys. How many different ways can they be seated if the boys cannot sit next to eachother. Solve both independently and dependently. \r
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Algebra.Com's Answer #181131 by stanbon(75887)\"\" \"About 
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Please help me answer this word problem: Mrs. Smith takes her class of 12 students to the theater.
\n" ); document.write( "They sit in the front row where there is exactly twelve seats.
\n" ); document.write( "There are 9 girls and 3 boys.
\n" ); document.write( "How many different ways can they be seated if the boys cannot sit next to each other.
\n" ); document.write( "Solve both independently and dependently.
\n" ); document.write( "I am not sure how to begin this problem.
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\n" ); document.write( "There are 12C3 ways to place the boys without restriction.
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\n" ); document.write( "There are 2*9 ways to place the boys if they all sit together.
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\n" ); document.write( "If 2 boys sat together there would be 9 ways to place the 3rd
\n" ); document.write( "boy without the 3 sitting together. And 2 boys can sit together
\n" ); document.write( "in 11 ways. So there are 11*9 ways of having a 2 boy/1boy split.
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\n" ); document.write( "Your Problem:
\n" ); document.write( "If no boys can sit next to one another: 12C3-18-99 = 220-117 = 103 ways
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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