document.write( "Question 248519: Please help me help my son with this word problem ...\r
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document.write( "A boat travels 60 km upstream (against the current) in 5 hours. The boat travels the same distance downstream in 3 hours. What is the rate of the boat in still water? What is the rate of the current? \n" );
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Algebra.Com's Answer #181125 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! We start with what we know about distance problems. \n" ); document.write( "d = r * t, where d=distance, r=rate, and t=time \n" ); document.write( ". \n" ); document.write( "Upstream info: \n" ); document.write( "60=r*5 \n" ); document.write( "r = 12 mph \n" ); document.write( ". \n" ); document.write( "Downstream \n" ); document.write( "60 = r*3 \n" ); document.write( "r = 20 \n" ); document.write( ". \n" ); document.write( "We need to assume the boat runs as fast as possible in both directions, otherwise we cannot solve the problem. \n" ); document.write( ". \n" ); document.write( "Let's call the upstream rate: U \n" ); document.write( "Let's call the downstream rate: D \n" ); document.write( "Let's call the unknown maximum rate: X \n" ); document.write( "And finally, the current is flowing at C mph. \n" ); document.write( ". \n" ); document.write( "Upstream: \n" ); document.write( "U = X-C \n" ); document.write( "In English, the upstream rate = max speed of the boat MINUS the current flowing against it.; \n" ); document.write( "X - C = 12, as shown above. \n" ); document.write( ". \n" ); document.write( "Downstream: \n" ); document.write( "D = X + C \n" ); document.write( "In English, the downstream rate = max speed of the boat PLUS the current pushing it along. \n" ); document.write( "X+C=20 \n" ); document.write( ". \n" ); document.write( "So we have two equations and two unknowns. Piece of cake. Right? \n" ); document.write( "X - C = 12 \n" ); document.write( "X + C = 20 \n" ); document.write( ". \n" ); document.write( "Let's add them. \n" ); document.write( "2X = 32 \n" ); document.write( "X = 16 \n" ); document.write( ". \n" ); document.write( "So the unknown maximum speed X is 16. \n" ); document.write( ". \n" ); document.write( "Now we check our work, as we always do... \n" ); document.write( ". \n" ); document.write( "Looking back at what we know, \n" ); document.write( "X-C = 12 \n" ); document.write( "16-C=12 \n" ); document.write( "C=4 \n" ); document.write( "OK \n" ); document.write( ". \n" ); document.write( "And we know \n" ); document.write( "X+C = 20 \n" ); document.write( "16 + C = 20 \n" ); document.write( "C=4 \n" ); document.write( ". \n" ); document.write( "Checking the upstream rate... \n" ); document.write( "60/(16-4)= 60/12 = 5, which is how long we were told it took. \n" ); document.write( "Checking the downstream rate... \n" ); document.write( "60/(16+4) = 60/20 = 3, which is how long we were told it took. \n" ); document.write( "Done. \n" ); document.write( " |