document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=248489>Question 248489</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the measures of any triangle is 180 degrees. Find the angle measures of a triangl if the second angle measures 10 degerees less than twice the first, and the third angle measures 25 degrees more than the second. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #181108 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=181108\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have 3 angles:  a, b & c.<BR>\n" );
document.write( "a + b + c = 180<BR>\n" );
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document.write( "To define the equations, you can just start with a.<BR>\n" );
document.write( "a = ?<BR>\n" );
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document.write( "b = 2a - 10   (twice a minus 10)<BR>\n" );
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document.write( "c = b + 25  (25 more than b)<BR>\n" );
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document.write( "Substitute for b<BR>\n" );
document.write( "c = (2a-10) + 25<BR>\n" );
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document.write( "Now substitute back into a+b+c=180<BR>\n" );
document.write( "a + (2a-10) + (2a-10+25) = 180<BR>\n" );
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document.write( "Eliminate the parentheses<BR>\n" );
document.write( "a + 2a - 10 + 2a - 10 + 25 = 180<BR>\n" );
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document.write( "Combine like terms<BR>\n" );
document.write( "5a + 5 = 180<BR>\n" );
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document.write( "Subtract 5 from both sides<BR>\n" );
document.write( "5a = 175<BR>\n" );
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document.write( "Divide both sides by 5<BR>\n" );
document.write( "a = 35<BR>\n" );
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document.write( "Substitute into the equation for b.<BR>\n" );
document.write( "b = 2a -10 = 2*35 - 10 = 70 - 10 = 60<BR>\n" );
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document.write( "Add 25 to b to get c.<BR>\n" );
document.write( "c = 60 + 25 = 85<BR>\n" );
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document.write( "Check by adding them up.<BR>\n" );
document.write( "35 + 60 + 85 = 180<BR>\n" );
document.write( "Done. </SPAN>\n" );
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