document.write( "Question 248482: The sum of the measures of any triangle is 180 degrees. Find the angle measures of a triangl if the second angle measures 10 degerees less than twice the first, and the third angle measures 25 degrees more than the second. \n" ); document.write( "
Algebra.Com's Answer #181092 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
Let a,b and c be the angles of the triangle.
\n" ); document.write( "a+b+c=180
\n" ); document.write( "b=2a-10
\n" ); document.write( "solve for a
\n" ); document.write( "b+10=2a
\n" ); document.write( "(b+10)/2=a
\n" ); document.write( "c=b+25
\n" ); document.write( "We now have three equations with three variables.\r
\n" ); document.write( "\n" ); document.write( "a=35
\n" ); document.write( "b=60
\n" ); document.write( "c=85
\n" ); document.write( "but how did we get that.
\n" ); document.write( "first substitute b+25 for c
\n" ); document.write( "(b+10)/2+b+b+25=180
\n" ); document.write( "consolidate
\n" ); document.write( "(b+10)/2+2b+25=180
\n" ); document.write( "subtract 25 from both sides
\n" ); document.write( "(b+10)/2+2b=155
\n" ); document.write( "multiply by 2 (both sides)
\n" ); document.write( "b+10+4b=310
\n" ); document.write( "subtract 10 (both sides)
\n" ); document.write( "b+4b=300
\n" ); document.write( "combine
\n" ); document.write( "5b=300
\n" ); document.write( "divide by 5(both sides)
\n" ); document.write( "b=60
\n" ); document.write( "c=b+25=25+60=85
\n" ); document.write( "a=(b+10)/2=(60+10)/2=70/2=35\r
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