document.write( "Question 248366: A 50-gon is a polygon with 50 sides. How could you find the sum of the angles in a 50-gon? What is the answer? \n" ); document.write( "
Algebra.Com's Answer #181002 by josmiceli(19441)\"\" \"About 
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First, draw lines from each vertex to some common point inside the figure
\n" ); document.write( "If I start going part way around the polygon, and look only at the triangles
\n" ); document.write( "formed by the lines I just drew, I add up the interior angles of each triangle.
\n" ); document.write( "If the angle in the center of the 1st triangle is \"A\", it's angles add ip to
\n" ); document.write( "\"180+-+A\", and for the 2nd triangle,
\n" ); document.write( "\"180+-+B\", and for the 3rd triangle,
\n" ); document.write( "\"180+-+C\"
\n" ); document.write( "There are exactly \"50\" of these triangles, so adding up all their angles, I get
\n" ); document.write( "\"50%2A180\" - (A + B + C + D + . . .)
\n" ); document.write( "I will run out of letters, but there must be \"50\" of them. Since they go
\n" ); document.write( "completely around the interior point of the polygon, they add up to \"360\" degress, so
\n" ); document.write( "\"50%2A180+-+360\" degrees is the answer
\n" ); document.write( "\"50%2A180+-+360+=+9000+-+360\"
\n" ); document.write( "\"9000+-+360+=+8640\" degrees
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