document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4106>Question 4106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 apples cost as much as 4 pears,  3 pears cost as much as 2 oranges.\r<BR>\n" );
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document.write( "How many apples cost the same as 72 oranges<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1810 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1810\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A = cost of 1 apple.<BR>\n" );
document.write( "Let P = cost of 1 pear.<BR>\n" );
document.write( "Let (Or) = cost of 1 orange.\r<BR>\n" );
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document.write( "(1)  3A = 4P  So, P = (3/4)A   Substitute into (2) below.<BR>\n" );
document.write( "(2)  3P = 2(Or)   \r<BR>\n" );
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document.write( " (2a) 3(3/4)A = 2(Or)  Divide both sides by 2.<BR>\n" );
document.write( "             (Or) = (9/8)A    Multiply both sides by 72.<BR>\n" );
document.write( "         72(Or) = 72(9/8)A  <BR>\n" );
document.write( "         72(Or) = 81A\r<BR>\n" );
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document.write( "So, 81 Apples cost the same as 72 Oranges. </SPAN>\n" );
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