document.write( "Question 31372: A company wants to invest $180,000 in three accounts, one bearing 4.5%, another 6%, and another 8% interest. Twice as much will be invested at 4.5% as at 8%, and the total interest earned the first year is $10,400. How much should be invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #18098 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
the equation is
\n" ); document.write( " $\"+.045%2A+2+%2A+x+%2B+.08+%2A+x+%2B+%28180%2A10%5E3+-+3%2Ax%29%2A+.06+=+10.4+%2A10%5E3\"$
\n" ); document.write( " $\".09%2Ax+%2B+.08%2Ax+-+.18%2Ax+%2B+10.8%2A10%5E3+=+10.4%2A10%5E3\"$
\n" ); document.write( " $\".17%2Ax+-+.18%2Ax+=+-400\"$
\n" ); document.write( " $\"-.01%2Ax+=+-400\"$
\n" ); document.write( " $\"x+=+40%2A10%5E3\"$
\n" ); document.write( "the amounts to be invested are
\n" ); document.write( "80K @ 4.5%
\n" ); document.write( "40K @ 8%
\n" ); document.write( "60K @ 6%
\n" ); document.write( "check
\n" ); document.write( "

\n" ); document.write( " 3.6K + 3.2K + 3.6K = 10.4K
\n" ); document.write( "OK \n" ); document.write( "

\n" );