document.write( "Question 248342: What number am I?\r
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document.write( "I am a three-digit number.
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document.write( "I am less than 200.
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document.write( "I am divisible by 12, and by 9.
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document.write( "My units digit is less than my tens digit. \n" );
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Algebra.Com's Answer #180979 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! let x=number \n" ); document.write( "100a+10b+c=x \n" ); document.write( "I am a three-digit number. \n" ); document.write( "I am less than 200. \n" ); document.write( "This tells me that the digit for hundreds is 1 \n" ); document.write( "It is a three digit number less than 200 \n" ); document.write( "Three digits numbers start with 100 \n" ); document.write( "so a=1\r \n" ); document.write( "\n" ); document.write( "I am divisible by 12, and by 9. \n" ); document.write( "divisible by 12 \n" ); document.write( "108, 120, 132, 144, 156,168,180,192\r \n" ); document.write( "\n" ); document.write( "My units digit is less than my tens digit.\r \n" ); document.write( "\n" ); document.write( "120, 132,180 and 192 \n" ); document.write( "divisible by 9 \n" ); document.write( "180\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |