document.write( "Question 248291: F(x)= x^3 - 6x2 +13x - 10\r
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document.write( "Find all the zeros of the function\r
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document.write( "thx! \n" );
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Algebra.Com's Answer #180977 by edjones(8007)![]() ![]() You can put this solution on YOUR website! x^3 - 6x2 +13x - 10=0 \n" ); document.write( "do the rational roots test by dividing +- a/d = +- 10/1 \n" ); document.write( "The possible rational factors are +- 10, 5, 2, 1 \n" ); document.write( "testing these we find that 2 is a zero. \n" ); document.write( "next we divide x^3 - 6x2 +13x - 10 by x-2 and get x^2-4x+5 which is a quadratic. \n" ); document.write( "x^2-4x+5=0 \n" ); document.write( "x^2-4x =-5 \n" ); document.write( "x^2-4x+4=-5+4 completing the square. \n" ); document.write( "(x-2)^2=-1 \n" ); document.write( "x-2=+-sqrt(-1) \n" ); document.write( "x=2+i, x=2-i the other 2 zeros. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |