document.write( "Question 248291: F(x)= x^3 - 6x2 +13x - 10\r
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Algebra.Com's Answer #180977 by edjones(8007)\"\" \"About 
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x^3 - 6x2 +13x - 10=0
\n" ); document.write( "do the rational roots test by dividing +- a/d = +- 10/1
\n" ); document.write( "The possible rational factors are +- 10, 5, 2, 1
\n" ); document.write( "testing these we find that 2 is a zero.
\n" ); document.write( "next we divide x^3 - 6x2 +13x - 10 by x-2 and get x^2-4x+5 which is a quadratic.
\n" ); document.write( "x^2-4x+5=0
\n" ); document.write( "x^2-4x =-5
\n" ); document.write( "x^2-4x+4=-5+4 completing the square.
\n" ); document.write( "(x-2)^2=-1
\n" ); document.write( "x-2=+-sqrt(-1)
\n" ); document.write( "x=2+i, x=2-i the other 2 zeros.
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\n" ); document.write( "Ed
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