document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=248299>Question 248299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Peanuts cost $3 per pound, almonds $4 per pound and cashews $8 per pound.  How many pounds of each should be used to produce 140 pounds of mixture costing $6 per pound, in which there are twice as many peanuts as almonds? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180949 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180949\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Peanuts cost $3 per pound, almonds $4 per pound and cashews $8 per pound. How many pounds of each should be used to produce 140 pounds of mixture costing $6 per pound, in which there are twice as many peanuts as almonds?<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "p = 2a<BR>\n" );
document.write( "p + a + c = 140<BR>\n" );
document.write( "3p + 4a + 8c = 6*140<BR>\n" );
document.write( "-------------------------<BR>\n" );
document.write( "Substitute into the 2nd and the 3rd equation:<BR>\n" );
document.write( "3a + c = 140<BR>\n" );
document.write( "10a+8c = 840<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "Multiply thru the 1st Eq by 8:<BR>\n" );
document.write( "24a + 8c = 8*140<BR>\n" );
document.write( "10a + 8c = 840<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Subtract the 2nd from the 1st and solve for \"a\":<BR>\n" );
document.write( "14a = 280<BR>\n" );
document.write( "a = 20 (amt. of almonds in the mix)<BR>\n" );
document.write( "p = 2a = 40 (amt of peanuts in the mix)<BR>\n" );
document.write( "c + 3a = 140<BR>\n" );
document.write( "c + 60 = 140<BR>\n" );
document.write( "c = 80 (amt of cashews in the mix)<BR>\n" );
document.write( "===========================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );