document.write( "Question 248253: I'm having difficulty with this problem: If an object is propelled upward from the ground level with an initial velocity of 224 ft per second, it's height \"h\" in feet \"t\" seconds later is given by the equation h=224t-16t^2. After how many seconds does the object hit the ground?
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Algebra.Com's Answer #180927 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"h=224t-16t%5E2\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"0=224t-16t%5E2\" Plug in \"h=0\" since the height at the ground level is zero.\r
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\n" ); document.write( "\n" ); document.write( "\"-16t%5E2%2B224t=0\" Rearrange the equation and terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-16t%28t-14%29=0\" Factor out the GCF -16t\r
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\n" ); document.write( "\n" ); document.write( "\"-16t=0\" or \"t-14=0\" Set each factor equal to zero.\r
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\n" ); document.write( "\n" ); document.write( "\"t=0\" or \"t=14\" Solve for 't' in each equation\r
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\n" ); document.write( "\n" ); document.write( "So the object will be at the ground level when t=0 or t=14. Ignoring the trivial answer of 0, this means that the object will hit the ground after 14 seconds.
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