document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=248248>Question 248248</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, kind tutor!<BR>\n" );
document.write( "Having a work problem concerning dilutions, and therefore ratios.<BR>\n" );
document.write( "We took 30 microliters of a stock, and added it to 270 microliters of saline to make 300 microliters of a 1:10 dilution. We then took this 300 microliters and added 100 microliters of another solution to that to form 400 microliters total. \r<BR>\n" );
document.write( "\n" );
document.write( "2 questions regarding this: What would the second dilution (300 microliters + 100 microliters) be considered? 3:4?<BR>\n" );
document.write( "And, what would the final dilution be? \r<BR>\n" );
document.write( "\n" );
document.write( "My boss and another coworker said it would end up being 1:13.3, (roughly 1:13), but I could not understand how they arrived at that number. \r<BR>\n" );
document.write( "\n" );
document.write( "Thank you very much for your kind assistance,<BR>\n" );
document.write( "Lauren </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180920 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180920\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Having a work problem concerning dilutions, and therefore ratios.<BR>\n" );
document.write( "-----------------------------<BR>\n" );
document.write( "We took 30 microliters of a stock, and added it to 270 microliters of saline to make 300 microliters of a 1:10 dilution.\r<BR>\n" );
document.write( "\n" );
document.write( "We then took this 300 microliters and added 100 microliters of another solution (with no active ingrediant) to that to form 400 microliters total.<BR>\n" );
document.write( " <BR>\n" );
document.write( "2 questions regarding this: What would the second dilution (300 microliters + 100 microliters) be considered? 3:4?<BR>\n" );
document.write( "And, what would the final dilution be? <BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.10*300 + 0*100 = x(300+100)<BR>\n" );
document.write( "30 + 0 = 400x<BR>\n" );
document.write( "x = 30/400<BR>\n" );
document.write( "x = 3/40 <BR>\n" );
document.write( "The ratio of active ingrediant to non-active in the final solution is 3:40<BR>\n" );
document.write( "or 1:13 1/3<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Congratualate your co-workers<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );