document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=248240>Question 248240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the third, sixth and eighth terms of the sequence A(n) = 6 + (n - 1)(-2). Step by step please, how do I get there ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180916 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the third, sixth and eighth terms of the sequence A(n) = 6 + (n - 1)(-2). Step by step please, how do I get there ?<BR>\n" );
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document.write( "A(n) = 6 + (n - 1)(-2)<BR>\n" );
document.write( "A(3) = 6 + 2(-2) = 2<BR>\n" );
document.write( "A(6) = 6 + 5(-2) = -4<BR>\n" );
document.write( "A(8) = 6 + 7(-2) = -8<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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