document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=248199>Question 248199</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pls. help me \r<BR>\n" );
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document.write( "The longer side of a rectangle is 4 less than twice the shorter side. The perimeter of the rectangle is 40. Find the length of each side of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180885 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180885\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The longer side of a rectangle is 4 less than twice the shorter side. The perimeter of the rectangle is 40. Find the length of each side of the rectangle.<BR>\n" );
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document.write( "Let the shorter side be \"x\".<BR>\n" );
document.write( "The longer side is \"2x-4\".<BR>\n" );
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document.write( "Perimeter = 2(shorter + longer)<BR>\n" );
document.write( "40 = 2(x + 2x-4)<BR>\n" );
document.write( "20 = 3x-4<BR>\n" );
document.write( "3x = 24<BR>\n" );
document.write( "x = 8 units (shorter side; there are 2 \"shorter\" sides)<BR>\n" );
document.write( "2x-4 = 16-4 = 12 (longer side; there are 2 \"longer sides)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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