document.write( "Question 248121: Walt made an extra $5000 last year from a part-time job. He invested part of the money at 6% and the rest at 10%. He made a total of $420 in interest. How much was invested at 10%? \n" ); document.write( "
Algebra.Com's Answer #180853 by tutorcecilia(2152)\"\" \"About 
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Walt made an extra $5000 last year from a part-time job. He invested part of the money at 6% and the rest at 10%. He made a total of $420 in interest. How much was invested at 10%?\r
\n" ); document.write( "\n" ); document.write( "Use: x+y=c
\n" ); document.write( "So, x+y=5000
\n" ); document.write( "y=50000-x
\n" ); document.write( "and
\n" ); document.write( "Use: ax+by=total
\n" ); document.write( "So, .06x+.10y=420
\n" ); document.write( ".06x+.10(5000-x)=420 [substitute y=5000-x)
\n" ); document.write( ".06x+500-.10x=420
\n" ); document.write( ".06x-.10x=420-500
\n" ); document.write( "-.04x=-80
\n" ); document.write( "-0.4x/.04=-80/-.04
\n" ); document.write( "x=2000
\n" ); document.write( "Substituting: 2000+y=5000
\n" ); document.write( "y=3000
\n" ); document.write( "answer: y=$3000
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