document.write( "Question 248121: Walt made an extra $5000 last year from a part-time job. He invested part of the money at 6% and the rest at 10%. He made a total of $420 in interest. How much was invested at 10%? \n" ); document.write( "
Algebra.Com's Answer #180853 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! Walt made an extra $5000 last year from a part-time job. He invested part of the money at 6% and the rest at 10%. He made a total of $420 in interest. How much was invested at 10%?\r \n" ); document.write( "\n" ); document.write( "Use: x+y=c \n" ); document.write( "So, x+y=5000 \n" ); document.write( "y=50000-x \n" ); document.write( "and \n" ); document.write( "Use: ax+by=total \n" ); document.write( "So, .06x+.10y=420 \n" ); document.write( ".06x+.10(5000-x)=420 [substitute y=5000-x) \n" ); document.write( ".06x+500-.10x=420 \n" ); document.write( ".06x-.10x=420-500 \n" ); document.write( "-.04x=-80 \n" ); document.write( "-0.4x/.04=-80/-.04 \n" ); document.write( "x=2000 \n" ); document.write( "Substituting: 2000+y=5000 \n" ); document.write( "y=3000 \n" ); document.write( "answer: y=$3000 \n" ); document.write( " \n" ); document.write( " |