document.write( "Question 248067: using the quadratic formula, what is the length and width of a rectangle if the length is 3 inches longer than twice the width and the area of the rectangle is 5 in^2? \n" ); document.write( "
Algebra.Com's Answer #180811 by oberobic(2304)\"\" \"About 
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L = 2W + 3 (length = twice the width + 3)
\n" ); document.write( "A = L * W = 5 square inches
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\n" ); document.write( "Substituting what we know.
\n" ); document.write( "A = (2W +3) * W = 5
\n" ); document.write( "2W^2 + 3W = 5
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\n" ); document.write( "Subtract 5 from both sides
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\n" ); document.write( "2W^2 + 3W - 5 = 0
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\n" ); document.write( "We do not need to use the quadratic to solve this because it can be factored.
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\n" ); document.write( "(2W + 5)(W - 1) = 0
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\n" ); document.write( "So we have two candidate values for W: W = 1 and W = -5/2.
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\n" ); document.write( "Since it is not possible to have a negative value for the width, W =1 is the candidate answer.
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\n" ); document.write( "L = 2W + 3
\n" ); document.write( "L = 2(1) + 3
\n" ); document.write( "L = 5
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\n" ); document.write( "Our candidate answer is:
\n" ); document.write( "L = 5
\n" ); document.write( "W = 1
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\n" ); document.write( "Checking the work.
\n" ); document.write( "Is L*W = 5? yes.
\n" ); document.write( "So, we accept that answer. \n" ); document.write( "
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