document.write( "Question 247911: I can't understand how to graph this, or were to put the points.\r
\n" ); document.write( "\n" ); document.write( "The problem is 6x + 3y = -12
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Algebra.Com's Answer #180810 by ankor@dixie-net.com(22740)\"\" \"About 
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I can't understand how to graph this, or were to put the points.
\n" ); document.write( "The problem is 6x + 3y = -12
\n" ); document.write( ":
\n" ); document.write( "First you want to put into the slope intercept form (y = mx + b)
\n" ); document.write( "6x - 3y = -12
\n" ); document.write( "-3y = -6x - 12
\n" ); document.write( "y has to be positive, multiply by -1; changes the signs
\n" ); document.write( "3y = 6x + 12
\n" ); document.write( "Divide eq by 3
\n" ); document.write( "y = 2x + 4
\n" ); document.write( ":
\n" ); document.write( "Select a value for x and find y
\n" ); document.write( "x = 3
\n" ); document.write( "y = 2(3) + 4
\n" ); document.write( "y = 6 + 4
\n" ); document.write( "y = 10
\n" ); document.write( "graph the point, 3,10
\n" ); document.write( ":
\n" ); document.write( "x = -3
\n" ); document.write( "y = 2(-3) + 4
\n" ); document.write( "y = -6 + 4
\n" ); document.write( "y = -2
\n" ); document.write( "graph the point, -3,-2
\n" ); document.write( ":
\n" ); document.write( "You only need two points, but an easy point is x=0
\n" ); document.write( "y = 2(0) + 4
\n" ); document.write( "y = 4
\n" ); document.write( "graph the point, 0,4
\n" ); document.write( ":
\n" ); document.write( "Should look like this:
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-5%2C+5%2C+-10%2C+12%2C+2x%2B4%29+\"
\n" ); document.write( ":
\n" ); document.write( "Did this shed some light on graphing for you?
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