document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=248059>Question 248059</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble with this one.\r<BR>\n" );
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document.write( "2 solutions of h2so4.  one is 40% concentration and one is 25% concentration.  how much of each do I need to get 137 liters of 36% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180808 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 solutions of h2so4. one is 40% concentration and one is 25% concentration. how much of each do I need to get 137 liters of 36% solution?<BR>\n" );
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document.write( "acid + acid = acid<BR>\n" );
document.write( "0.40x + 0.25(137-x) = 0.36*137<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "40x + 25*137 - 25x = 36*137<BR>\n" );
document.write( "15x = 11*137<BR>\n" );
document.write( "x = 100.47 liters (amt. of 40% solution needed in the mixture)<BR>\n" );
document.write( "137-100.47 = 36.53 liters (amt of 25% solution in the mixture)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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