document.write( "Question 247904: Gideon is 30 years younger than his father. His mother is three times as old as her son. Find Gideon's age if his father is two years older than his mother. \n" ); document.write( "

Algebra.Com's Answer #180772 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Gideon is 30 years younger than his father.
\n" ); document.write( " His mother is three times as old as her son
\n" ); document.write( " Find Gideon's age if his father is two years older than his mother.
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\n" ); document.write( "Let g = Gideon's age
\n" ); document.write( "then
\n" ); document.write( "(g+30) = father's age
\n" ); document.write( "and
\n" ); document.write( "3g = mother's age
\n" ); document.write( ":
\n" ); document.write( "Father's age = mother age + 2 yrs
\n" ); document.write( "g+30 = 3g + 2
\n" ); document.write( "30 - 2 = 3g - g
\n" ); document.write( "28 = 2g
\n" ); document.write( "g = $\"28%2F2\"$
\n" ); document.write( "g = 14 yrs is Gideon's age
\n" ); document.write( ":
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\n" ); document.write( "Check solution
\n" ); document.write( "Father: 30 + 14 = 44
\n" ); document.write( "Mother: 3(14) = 42; 2 yrs less \n" ); document.write( "

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