document.write( "Question 247934: the vagabonds were 200 miles apart at 2 p.m. and were headed toward each other. if they met at 6 p.m. and one was traveling 10 miles per hour faster than the other,what was the speed of each vagabond? \n" ); document.write( "
Algebra.Com's Answer #180749 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! r4=200 \n" ); document.write( "r=50 mph combined speed \n" ); document.write( "2f+10=50 \n" ); document.write( "2f=40 \n" ); document.write( "f=20 \n" ); document.write( "f+10=30 \n" ); document.write( "or \n" ); document.write( "f*4+(f+10)*4=200 \n" ); document.write( "f*4+f*4+40=200 \n" ); document.write( "8f+40=200 \n" ); document.write( "8f=160 \n" ); document.write( "f=20 \n" ); document.write( "f+10=30 \n" ); document.write( "check \n" ); document.write( "4*20+4*30=200 \n" ); document.write( "80+120=200 \n" ); document.write( "200=200\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |