document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31160>Question 31160</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 6-foot-diameter disk and an 18-foot-diameter disk sit side by side.  Determine the shortest length of rope that will go around both disks.<BR>\n" );
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document.write( " my answer below is different from a friends with a program to figure it out. i am concerned that i am not doing it right.\r<BR>\n" );
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document.write( "For circles that are externally tangent the line of centers=the length of the sum of both radii= common external tangents\r<BR>\n" );
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document.write( "Line of centers 3+9=12<BR>\n" );
document.write( "Common external tangents=12*2=24\r<BR>\n" );
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document.write( "60 degrees because we will create a equilateral triangle\r<BR>\n" );
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document.write( "Arc 1<BR>\n" );
document.write( "Degrees (pi/180) r<BR>\n" );
document.write( "60(3.14/180) 3<BR>\n" );
document.write( "3.14\r<BR>\n" );
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document.write( "Arc 2<BR>\n" );
document.write( "60(3.14/180) 9<BR>\n" );
document.write( "9.42\r<BR>\n" );
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document.write( "Common external tangents+Arc 1+Arc2<BR>\n" );
document.write( "24+3.14+9.42<BR>\n" );
document.write( "36.56 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18074 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18074\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> GOOD TO SEE YOUR KEEN DESIRE TO DO BY YOUR SELF INSTEAD OF GOING BY A PROGRAMME <BR>\n" );
document.write( "SEE THE FOLLOWING DRAWING.IT IS SELF EXPLANATORY I SUPPOSE. LET US PROCEED FROM WHERE YOU ALREADY WORKED.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28600%2C600%2C0%2C30%2C0%2C30%2Cred%28+line%28+0%2C15%2C+24%2C15+%29+%29%2Clocate%28+0%2C+15%2C+A+%29%2Cred%28+line%28+0%2C0%2C0%2C30+%29+%29%2Clocate%28+3%2C15%2C+B+%29%2Clocate%28+6%2C+15%2C+C+%29%2Cred%28+line%28+1.5%2C17.6%2C10.5%2C22.8+%29+%29%2Clocate%28+15%2C15%2C+D+%29%2Clocate%28+24%2C+15%2C+E%29%2Clocate%281.5%2C17.6%2CF%29%2Clocate%2810.5%2C22.8%2CG+%29%2Clocate%2812%2C20.2%2CK%29%2Cred%28line%283%2C15%2C1.5%2C17.6%29%29%2Cred%28line%2815%2C15%2C10.5%2C22.8%29%29%2Cred%28line%283%2C15%2C12%2C20.2%29%29%2Ccircle%283%2C15%2C3%29%2Ccircle%2815%2C15%2C9%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "LET US ESTIMATE HALF THE LENGTH NAMELY AFGE AND DOUBLE IT TO GET THE TOTAL LENGTH. <BR>\n" );
document.write( "ARC AF =2*PI*3*60/360=3.14<BR>\n" );
document.write( "FG=COMMON TANGENT <BR>\n" );
document.write( "FG=BK=SQRT.{(9+3)^2-(9-3)^2}=SQRT.108=10.39<BR>\n" );
document.write( "ARC GE=2*PI*9*120/360=18.84<BR>\n" );
document.write( "TOTAL=ARC AF+FG+ARC GE = 3.14+10.39+18.84=32.37<BR>\n" );
document.write( "TOTAL LENGTH=2*32.37=64.74<BR>\n" );
document.write( " HOPE YOU KNOW HOW WE GOT 60 DEGREES AS SECTOR ANGLE!!!OTHERWISE I SHALL EXPLAIN YOU ON HEARING FROM YOU.<BR>\n" );
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