document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31069>Question 31069</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a side of one square is 3 inches greater than the length of a side of a second square.  If the area of the first square exceeds the area of the second by 51 squares inches, find the lengths of the sides of each square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18073 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume that the length of smaller square is x inch<BR>\n" );
document.write( "The length of the larger square is then (x+3)\r<BR>\n" );
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document.write( "Area of smaller Square = x^2<BR>\n" );
document.write( "Area of larger Square=(x+3)^2\r<BR>\n" );
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document.write( "Based on the question,\r<BR>\n" );
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document.write( "(x+3)^2 = x^2 + 51<BR>\n" );
document.write( "=>x^2 + 6x + 9 = x^2 + 51<BR>\n" );
document.write( "=>6x = 42<BR>\n" );
document.write( "=>x = 7\r<BR>\n" );
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document.write( "Length of the sides of the smaller square is 7 inch and the length of the side of the larger square is 10 inch. </SPAN>\n" );
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