document.write( "Question 247755: Find the area of a regular hexagon with the given measurement 4 inches\r
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document.write( "for that answer I got 25 square root of 3\r
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document.write( "the area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. find the length of a side of the regular hexagon/
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document.write( " I got 2 and the square root of 4\r
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Algebra.Com's Answer #180722 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Find the area of a regular hexagon with the given measurement 4 inches \r \n" ); document.write( "\n" ); document.write( "for that answer I got 25 square root of 3 \n" ); document.write( "For any regular polygon with n sides of length s: \n" ); document.write( "Area = (ns^2/4)*cot(180/n) \n" ); document.write( "= 6*16*cot(30)/4 \n" ); document.write( "= 24*sqrt(3) \n" ); document.write( "------------- \n" ); document.write( "the area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. find the length of a side of the regular hexagon/ \n" ); document.write( "I got 2 and the square root of 4 \n" ); document.write( "Area of the triangle = (3*144/4)*cot(60) \n" ); document.write( "Area = 108*cot(60) \n" ); document.write( "Area = 36*sqrt(3) \n" ); document.write( "------------------ \n" ); document.write( "36*sqrt(3) = (6s^2/4)*cot(30) = (3s^2/2)*sqrt(3) \n" ); document.write( "3s^2 = 72 \n" ); document.write( "x = 2sqrt(6) \n" ); document.write( " \n" ); document.write( " |