document.write( "Question 247755: Find the area of a regular hexagon with the given measurement 4 inches\r
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\n" ); document.write( "\n" ); document.write( "for that answer I got 25 square root of 3\r
\n" ); document.write( "\n" ); document.write( "the area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. find the length of a side of the regular hexagon/
\n" ); document.write( " I got 2 and the square root of 4\r
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Algebra.Com's Answer #180722 by Alan3354(69443)\"\" \"About 
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Find the area of a regular hexagon with the given measurement 4 inches \r
\n" ); document.write( "\n" ); document.write( "for that answer I got 25 square root of 3
\n" ); document.write( "For any regular polygon with n sides of length s:
\n" ); document.write( "Area = (ns^2/4)*cot(180/n)
\n" ); document.write( "= 6*16*cot(30)/4
\n" ); document.write( "= 24*sqrt(3)
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\n" ); document.write( "the area of a given hexagon is equal to the area of an equilateral triangle whose perimeter is 36 inches. find the length of a side of the regular hexagon/
\n" ); document.write( "I got 2 and the square root of 4
\n" ); document.write( "Area of the triangle = (3*144/4)*cot(60)
\n" ); document.write( "Area = 108*cot(60)
\n" ); document.write( "Area = 36*sqrt(3)
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\n" ); document.write( "36*sqrt(3) = (6s^2/4)*cot(30) = (3s^2/2)*sqrt(3)
\n" ); document.write( "3s^2 = 72
\n" ); document.write( "x = 2sqrt(6)
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