document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=247756>Question 247756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I calculate side BC of an Isosceles triangle when the two equal sides AB and AC are 12 and angle A [BAC] is 130°??\r<BR>\n" );
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document.write( "Thank you for any help\r<BR>\n" );
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document.write( "Jasmine </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180711 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I calculate side BC of an Isosceles triangle when the two equal sides AB and AC are 12 and angle A [BAC] is 130°?? <BR>\n" );
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document.write( "You can use the Law of Sines:<BR>\n" );
document.write( "a/sin(A) = b/sin(B)<BR>\n" );
document.write( "Angles B and C are 25 degs (since it's an isosceles)<BR>\n" );
document.write( "a = 12*sin(130)/sin(25)<BR>\n" );
document.write( "a =~ 21.75<BR>\n" );
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document.write( "You can also drop an altitude from A.  Then a/2 = 12*sin(65)<BR>\n" );
document.write( "a = 24*sin(65)<BR>\n" );
document.write( "a =~ 21.75 (again, it's monotonous)<BR>\n" );
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